Question

How do you find `(f-g)(x)` given `f(x)=x^2-1 and`g(x)=2x-3`and`h(x)=1-4x#?

Answer 1

See the entire solution process below:

Explanation:

`(f - g)(x) = f(x) - g(x) = (x^2 - 1) - (2x - 3)`

`(f - g)(x) = x^2 - 1 - 2x + 3`

`(f - g)(x) = x^2 - 2x + 3 - 1`

`(f - g)(x) = x^2 - 2x + 2`

The `h(x)` is not used and is extraneous and unnecessary information for this problem.