How do you find #(f+g)(x)# given #f(x)=x^2-1 and #g(x)=2x-3# and #h(x)=1-4x#?

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Answer 1 · 2018-03-20T12:57:07

See a solution process below:

We can rewrite #(f + g)(x)# as:

#(f + g)(x) = f(x) + g(x)#

Substituting gives:

#(f + g)(x) = (x^2 - 1) + (2x - 3)#

#(f + g)(x) = x^2 - 1 + 2x - 3#

#(f + g)(x) = x^2 + 2x - 1 - 3#

#(f + g)(x) = x^2 + 2x + (-1 - 3)#

#(f + g)(x) = x^2 + 2x + (-4)#

#(f + g)(x) = x^2 + 2x - 4#