Question

How do you find `(f*g)(x)` given `f(x)=x^2-1 and`g(x)=2x-3`and`h(x)=1-4x#?

Answer 1

See a solution process below:

Explanation:

`(f * g)(x) = (x^2 - 1)(2x - 3)`

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

`(f * g)(x) = (color(red)(x^2) - color(red)(1))(color(blue)(2x) - color(blue)(3))` becomes:

`(f * g)(x) = (color(red)(x^2) xx color(blue)(2x)) - (color(red)(x^2) xx color(blue)(3)) - (color(red)(1) xx color(blue)(2x)) + (color(red)(1) xx color(blue)(3))`

`(f * g)(x) = 2x^3 - 3x^2 - 2x + 3`