Question

How do you find `(f+h)(0)` given `f(x)=x^2-1 and`g(x)=2x-3`and`h(x)=1-4x#?

Answer 1

See below.

Explanation:

`(f+h)(0)=f(0)+h(0)`.

Given that `f(x)=x^2-1`,

`f(0)=0^2-1=-1`

`h(0)=1-4(0)=1`

Thus,

`(f+h)(0)=f(0)+h(0)=-1+1=0`.