How do you find #f(h(7))# given #f(x)=2x-1# and #g(x)=3x# and #h(x)=x^2+1#?

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Answer 1 · 2017-03-07T08:52:00

#f(h(7)) = 99#

First we can ignore #g(x)# since it plays no part in the calculation.

We are told that: # h(x) = x^2+1# and #f(x) = 2x-1#

We are asked to find #f(h(7))#

Considering #f(h(7))# in two steps:

(i) #h(7) = 7^2+1 = 49+1=50#

(ii) #f(50) = 2*50-1 = 100-1 = 99#

Hence: #f(h(7)) = 99#