# How do you find f(h(7)) given f(x)=2x-1 and g(x)=3x and h(x)=x^2+1?

##### 1 Answer
Mar 7, 2017

$f \left(h \left(7\right)\right) = 99$

#### Explanation:

First we can ignore $g \left(x\right)$ since it plays no part in the calculation.

We are told that: $h \left(x\right) = {x}^{2} + 1$ and $f \left(x\right) = 2 x - 1$

We are asked to find $f \left(h \left(7\right)\right)$

Considering $f \left(h \left(7\right)\right)$ in two steps:

(i) $h \left(7\right) = {7}^{2} + 1 = 49 + 1 = 50$

(ii) $f \left(50\right) = 2 \cdot 50 - 1 = 100 - 1 = 99$

Hence: $f \left(h \left(7\right)\right) = 99$