How do you find #f(x+1)# given #f(x)=2x-1# and #g(x)=3x# and #h(x)=x^2+1#?
1 Answer
May 26, 2017
Explanation:
#"to evaluate " f(x+1)" substitute " x=x+1" in " f(x)#
#f(color(red)(x+1))=2(color(red)(x+1))-1#
#color(white)(xxxxxx)=2x+2-1larr" distributing"#
#color(white)(xxxxxx)=2x+1#
