# How do you find g(1) given g(a)=3^(3a-2)?

Apr 17, 2017

See the entire solution process below:

#### Explanation:

To find $g \left(1\right)$ substitute $\textcolor{red}{1}$ for each occurrence of $a$ in the function $g \left(a\right)$:

$g \left(\textcolor{red}{a}\right) = {3}^{3 \textcolor{red}{a} - 2}$ becomes:

$g \left(\textcolor{red}{1}\right) = {3}^{\left(3 \cdot \textcolor{red}{1}\right) - 2}$

$g \left(\textcolor{red}{1}\right) = {3}^{3 - 2}$

$g \left(\textcolor{red}{1}\right) = {3}^{1}$

$g \left(\textcolor{red}{1}\right) = 3$