How do you find #g(3a)# given #f(x)=2x-1# and #g(x)=3x# and #h(x)=x^2+1#?
1 Answer
Mar 11, 2017
Explanation:
To evaluate g( 3a) substitute x = 3a into g( x)
#rArrg(color(red)(3a))=3xxcolor(red)(3a)=9a#
