# How do you find g(8) given g(n)=n^2+3?

$g \left(8\right) = {8}^{2} + 3 = 67$
Since $g \left(n\right) = {n}^{2} + 3$ and we already have $n = 8$ (from $g \left(8\right)$) , all we need to do it to replace $n$ with $8$ and apply this to the equation (seen above).