# How do you find g(a^2) given g(a)=3a-3?

Mar 26, 2017

See the entire solution process below:

#### Explanation:

To find $g \left({a}^{2}\right)$ given $g \left(a\right)$ we must substitute $\textcolor{red}{{a}^{2}}$ for every occurrence of $\textcolor{red}{a}$ in the function:

$g \left(\textcolor{red}{a}\right) = 3 \textcolor{red}{a} - 3$ becomes:

$g \left(\textcolor{red}{{a}^{2}}\right) = 3 \textcolor{red}{{a}^{2}} - 3$

If required, this can be factored as follows:

$g \left(\textcolor{red}{{a}^{2}}\right) = 3 \left(\textcolor{red}{{a}^{2}} - 1\right)$

$g \left(\textcolor{red}{{a}^{2}}\right) = 3 \left(a + 1\right) \left(a - 1\right)$