Question

How do you find `(g-f)(a)` given `g(a)=-3a-3` and `f(a)=a^2+5`?

Answer 1

`(g-f)(a)=-a^2-3a-8`

Explanation:

`(g-f)(a)=g(a)-f(a)`

`rArr-3a-3-(a^2+5)`

`=-3a-3-a^2-5`

`=-a^2-3a-8`