# How do you find #g(h(24))# given #f(x)=2x-1# and #g(x)=3x# and #h(x)=x^2+1#?

##### 1 Answer

Mar 6, 2017

#### Explanation:

Evaluate g(h(24)) by first evaluating h(24)

#rArrh(color(red)(24))=(color(red)(24))^2+1#

#color(white)(rAerrh(24))=576+1#

#color(white)(rArrh(24)xx)=577# Now substitute this value into g(x)

#rArrg(h(24))=g(577)#

#=3xx577#

#=1731#