# How do you find g(t/4) given g(t)=t+3?

Aug 5, 2016

$g \left(\frac{t}{4}\right) = \frac{t + 12}{4}$

#### Explanation:

To evaluate $g \left(\frac{t}{4}\right)$

$\textcolor{b l u e}{\text{substitute t=t/4 into g(t)}}$

$\Rightarrow g \left(\textcolor{red}{\frac{t}{4}}\right) = \textcolor{red}{\frac{t}{4}} + 3$

We can express $\frac{t}{4} + 3 \text{ as a single fraction}$

$\Rightarrow \frac{t}{4} + \left(\frac{3}{1} \times \frac{4}{4}\right) = \frac{t}{4} + \frac{12}{4}$

we now have a common denominator and can add the numerators.

$\Rightarrow g \left(\frac{t}{4}\right) = \frac{t + 12}{4}$