How do you find #g(-x)# given #g(x)=x^2-3#?
1 Answer
Mar 5, 2018
Explanation:
#"substitute "x=-x" into "g(x)#
#rArrg(color(red)(-x))=(color(red)(-x))^2-3=x^2-3#
#"substitute "x=-x" into "g(x)#
#rArrg(color(red)(-x))=(color(red)(-x))^2-3=x^2-3#