How do you find general form of circle with center is (2,-3) and passes through (2, 7)?

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Answer 1 · 2018-06-06T12:39:51

Equation of the circle is $(x – 2)^2 + (y +3)^2 = 100$

The center-radius form of the circle equation is

$(x – h)^2 + (y – k)^2 = r^2$ , with the center being at the point

$(h=2, k=-3)$ and the radius being $r$ . The circle passes

through point $A(2,7) and C( 2,-3)$ is the center .

Distance formula is $AC=r= sqrt ((x_1-x_2)^2+(y_1-y_2)^2$

$r^2=(2-2)^2+(7-(-3))^2=100$ Hence equation of the

circle is $(x – 2)^2 + (y +3)^2 = 100$

graph{(x-2)^2+(y+3)^2=100 [-40, 40, -20, 20]}