How do you find #(goh)(1)# given #g(x)=x^2+4+2x# and #h(x)=-3x+2#?

1 Answer
Jim G.
Feb 17, 2017

#3#

Explanation:

Find (g○h)(x) = g(h(x)) to begin with.

#g(h(x))=g(color(red)(-3x+2))#

#color(white)(g(h(x)))=(color(red)(-3x+2))^2+4+2(color(red)(-3x+2))#

#color(white)(g(h(x)))=9x^2-12x+4+4-6x+4#

#color(white)(g(h(x)))=9x^2-18x+12#

#rArr(g￮h)(1)=(9xx1^2)-(18xx1)+12#

#color(white)(rArr(g￮h)(1))=9-18+12#

#color(white)(rArr(g￮h)(1))=3#

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