How do you find #(goh)(-4)# given #g(a)=2a-1# and #h(a)=3a-3#?
1 Answer
Apr 1, 2017
Explanation:
Note
#(g@h)=g(h(x))# To find g(h(a)) substitute h(a) into g(a)
#g(h(a))=g(color(red)(3a-3))=2(color(red)(3a-3))-1#
#=6a-6-1#
#=6a-7#
#rArr(g@h)(-4)#
#=(6xx-4)-7=-31#
