How do you find #(goh)(n)# given #g(n)=2n+3# and #h(n)=n-1#?

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Answer 1 · 2017-03-31T10:02:25

The answer is #=2n+1#

This is a composition of functions

#g(n)=2n+3#

#h(n)=n-1#

#(goh)(n)=g(h(n))#

#=g(n-1)#

#=2(n-1)+3#

#=2n-2+3#

#=2n+1#