How do you find (goh)(n) given g(n)=2n+3 and h(n)=n-1?

1 Answer
Mar 31, 2017

The answer is $= 2 n + 1$

Explanation:

This is a composition of functions

$g \left(n\right) = 2 n + 3$

$h \left(n\right) = n - 1$

$\left(g o h\right) \left(n\right) = g \left(h \left(n\right)\right)$

$= g \left(n - 1\right)$

$= 2 \left(n - 1\right) + 3$

$= 2 n - 2 + 3$

$= 2 n + 1$