# How do you find h(-1) given h(x)=-x^2-3?

Aug 30, 2017

See a solution process below:

#### Explanation:

To fing $h \left(- 1\right)$ substitute $\textcolor{red}{- 1}$ for each occurrence of $\textcolor{red}{- 1}$ and the calculate the result:

$h \left(\textcolor{red}{x}\right) = - {\textcolor{red}{x}}^{2} - 3$ becomes:

$h \left(\textcolor{red}{- 1}\right) = - {\textcolor{red}{\left(- 1\right)}}^{2} - 3$

$h \left(\textcolor{red}{- 1}\right) = - 1 - 3$

$h \left(\textcolor{red}{- 1}\right) = - 4$