How do you find #h(4)# given #h(n)=n^3+6n#?
1 Answer
May 27, 2017
Explanation:
#"to evaluate " h(4)" substitute " n=4" into " h(n)#
#h(color(red)(4))=(color(red)(4))^3+(6xxcolor(red)(4))#
#color(white)(h(4))=64+24#
#color(white)(h(4))=88#
