# How do you find h(6) given h(t)=abs(t+2)+3?

Oct 15, 2016

$h \left(6\right) = 11$

#### Explanation:

$h \left(6\right)$ tells you to replace $t$ with $6$ and simplify the expression.

$h \left(6\right) = | 6 + 2 | + 3$
$h \left(6\right) = | 8 | + 3$
$h \left(6\right) = 8 + 3$
$h \left(6\right) = 11$