# How do you find (h-g)(n) given h(n)=4n+5 and g(n)=3n+4?

Jul 3, 2017

$\left(h - g\right) \left(n\right) = n + 1$

#### Explanation:

To find the new function all you have to do is apply the operation in the order that is specified. In this case, subtract the two functions:

$\left(h - g\right) \left(n\right) = h \left(n\right) - g \left(n\right)$

$\Rightarrow \left(h - g\right) \left(n\right) = \left[4 n + 5\right] - \left[3 n + 4\right]$

$\Rightarrow \left(h - g\right) \left(n\right) = \left(4 n - 3 n\right) + \left(5 - 4\right) = n + 1$