How do you find (h-g)(t) given h(t)=2t+1 and g(t)=2t+2?

May 26, 2017

$\left(h - g\right) \left(t\right) = - 1$

Explanation:

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$h \left(t\right)$ is just an identifier for a particular process applied to the variable $t$

So $h \left(t\right) = 2 t + 1 \mathmr{and} h \left(s\right) = 2 s + 1 \mathmr{and} h \left(b\right) = 2 b + 1$

So $g \left(t\right) = 2 t + 2 \mathmr{and} g \left(s\right) = 2 s + 2 \mathmr{and} g \left(b\right) = 2 b + 2$
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The question can also be written as: $h \left(t\right) - g \left(t\right)$

$h \left(t\right) \to 2 t + 1$
$g \left(t\right) \to \underline{2 t + 2} \leftarrow \text{ subtract}$
$\text{ } 0 t - 1$

$\left(h - g\right) \left(t\right) = - 1$