Question

How do you find `h(n/2)` given `h(n)=-2n^3-5n`?

Answer 1

`h (n/2) = -n^3/4- (5n)/2`

Explanation:

`h (n) = -2n^3 - 5n`

`h (n/2) = -2(n/2)^3 - 5(n/2)` or

`h (n/2) = -2*n^3/8- 5*n/2` or

`h (n/2) = -n^3/4- (5n)/2` [Ans]