How do you find #h(n-3)# given #h(n)=-n-2#?

1 Answer
smendyka
Mar 17, 2017

See the entire solution process below:

Explanation:

To solve this function for #(n - 3)# we must substitute #color(red)((n - 3)# for every occurrence of #color(red)(n)# in #h(n)#:

#h(color(red)(n)) = -color(red)(n) - 2# becomes:

#h(color(red)(n - 3)) = -color(red)((n - 3)) - 2#

#h(color(red)(n - 3)) = -n + 3 - 2#

#h(color(red)(n - 3)) = -n + 1#

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