# How do you find h(n-3) given h(n)=-n-2?

Mar 17, 2017

See the entire solution process below:

#### Explanation:

To solve this function for $\left(n - 3\right)$ we must substitute color(red)((n - 3) for every occurrence of $\textcolor{red}{n}$ in $h \left(n\right)$:

$h \left(\textcolor{red}{n}\right) = - \textcolor{red}{n} - 2$ becomes:

$h \left(\textcolor{red}{n - 3}\right) = - \textcolor{red}{\left(n - 3\right)} - 2$

$h \left(\textcolor{red}{n - 3}\right) = - n + 3 - 2$

$h \left(\textcolor{red}{n - 3}\right) = - n + 1$