# How do you find h(x-2) given f(x)=2x-1 and g(x)=3x and h(x)=x^2+1?

Mar 12, 2017

$h \left(x - 2\right) = {x}^{2} - 4 x + 5$

#### Explanation:

To evaluate h( x - 2) substitute x = x - 2 in h( x)

$h \left(\textcolor{red}{x - 2}\right) = {\left(\textcolor{red}{x - 2}\right)}^{2} + 1$

$\textcolor{w h i t e}{x - 2 \times} = {x}^{2} - 4 x + 4 + 1$

$\textcolor{w h i t e}{\times \times \times} = {x}^{2} - 4 x + 5$