How do you find #h(x-2)# given #f(x)=2x-1# and #g(x)=3x# and #h(x)=x^2+1#?
1 Answer
Mar 12, 2017
Explanation:
To evaluate h( x - 2) substitute x = x - 2 in h( x)
#h(color(red)(x-2))=(color(red)(x-2))^2+1#
#color(white)(x-2xx)=x^2-4x+4+1#
#color(white)(xxxxxx)=x^2-4x+5#
