How do you find its inverse and check your answer and state the domain and the range of #f(x) = 4 /( x+2)# and f^-1?

1 Answer
Dec 8, 2017

Explained below

Explanation:

The domain: #D(f)= RR//{-2}#
#x+2!=0#
#x!=-2#

In order to find inverse function the following statement must be true:
For every #x_1//x_2 in D(f): x_1!=x_2 => f(x_1)!=f(x_2)#

Proof by contradiction:
#4/(x_1+2)=4/(x_2+2)#
#cancel4(x_2+cancel2)=cancel4(x_1+cancel2)#
#x_2=x_1#
So now we know that this function is simple and has an inverse function. Let's find it.

#y=4/(x+2)#

#x=4/(y+2)#

#x(y+2)=4#

#y+2=4/x#

#f^-1 : y=4/x-2#

If we want to find #H(f)# we have to find #D(f^-1)#. It's:
#x!=0#
so #H(f)=RR//{0}#

(english is not my native language which means you may use different way to solve it)