How do you find #k(-3t)# given #k(t)=-4t+2#?

1 Answer
Tony B
Jan 28, 2017

#k(-3t) =-12t-6#

Explanation:

The purpose of the letter k within the context of #k(t)# is that it is an identifyer for a particular structure of equation using the variable #t#

A different structure could for example be given the identifying name of #g(x)#. Yet another structure could be given the identifying name of #h(x)#.

Suppose #h(x)=3x^2-5x+2# then #h(t)=3t^2-5t+2#
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Just for the sake of clarity set #" "k(t)=s=-4t+2#

So#" "k(-3t) =-3s=-3(4t+2) = -12t-6#

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