How do you find #k(4-x)# given #k(x)=4x-4#?
1 Answer
Aug 27, 2016
Explanation:
Given:
#k(x) = 4x-4#
The variable
#k(t) = 4t-4#
Now substitute
#k(4-x) = 4(4-x) - 4#
#= 16-4x-4#
#= 12-4x#