How do you find #k(a-2)# given #k(a)=-4^(3a+2)#?
1 Answer
Sep 7, 2016
Explanation:
To evaluate k(a - 2) , substitute a = a - 2 into k(a)
#k(color(red)(a-2))=-4^(3(color(red)(a-2))+2# now
#3(a-2)+2=3a-6+2=3a-4#
#rArrk(a-2)=-4^(3a-4)#