# How do you find k(a-2) given k(a)=-4^(3a+2)?

Sep 7, 2016

$k \left(a - 2\right) = - {4}^{3 a - 4}$

#### Explanation:

To evaluate k(a - 2) , substitute a = a - 2 into k(a)

k(color(red)(a-2))=-4^(3(color(red)(a-2))+2

now $3 \left(a - 2\right) + 2 = 3 a - 6 + 2 = 3 a - 4$

$\Rightarrow k \left(a - 2\right) = - {4}^{3 a - 4}$