# How do you find lim (1-2t^-1+t^-2)/(3-4t^-1) as t->0?

Lim_"t->0"(1-2t^-1+t^-2)/(3-4t^-1)=±oo depending on if $t \to + \infty$ or $t \to - \infty$
$L i {m}_{\text{t->0}} \frac{1 - 2 {t}^{-} 1 + {t}^{-} 2}{3 - 4 {t}^{-} 1}$
=Lim_"t->0"(t²-2t+1)/(3t²-4t)
$= L i {m}_{\text{t->0}} - \frac{1}{4 t}$
=±oo depending on if $t \to + \infty$ or $t \to - \infty$