Question

How do you find `lim 1/root3(x)` as `x->0^+`?

Answer 1

`oo`

Explanation:

There is not much you can do here to manipulate `1/(root(3)(x)`, so observing:

`:.`

as `x->0^+` , `root(3)(x)->0` ( denominator is positve )

`:.`

`lim_(x->0^+)(1/root(3)(x))=oo`