# How do you find lim 1/root3(x) as x->0^+?

Jan 3, 2018

$\infty$

#### Explanation:

There is not much you can do here to manipulate 1/(root(3)(x), so observing:

$\therefore$

as $x \to {0}^{+}$ , $\sqrt[3]{x} \to 0$ ( denominator is positve )

$\therefore$

${\lim}_{x \to {0}^{+}} \left(\frac{1}{\sqrt[3]{x}}\right) = \infty$