# How do you find #lim (3+u^(-1/2)+u^-1)/(2+4u^(-1/2))# as #u->0^+# using l'Hospital's Rule?

##### 1 Answer

Feb 19, 2017

l"Hospital's Rule is neither needed nor helpful for this limit.

#### Explanation:

We do get the indeterminate form

Therefore, we will continue to get the indeterminate

Multiply by

We no longer get an indeterminate form, so we cannot use (and have no need for) l'Hospital's Rule.

(The numerator is going to a positive limit and the denominator is going to