Question

How do you find `lim (3x)/(4x-10)` as `x->-oo`?

Answer 1

`-3/4`

Explanation:

Ignore the -10 since it's irrelevant when you get to high numbers such as infinity so treat the limit as:

`lim (3x)/(4x)` as x→−∞

Cancel out the x's:

`lim (3)/(4)` as x→−∞

Now there are no more x's so `3/4` is your answer.