How do you find #lim (6x^3-4)/(2x+5)# as #x->oo#?
1 Answer
Apr 5, 2017
You should get
Explanation:
Consider the numerator first: even if you subtract
The denominator as well BUT not as fast as the numerator!
So the numerator will "win"and in the limit the function will tend to
We can also write collecting
as