# How do you find #lim (6x^3-4)/(2x+5)# as #x->oo#?

##### 1 Answer

Apr 5, 2017

You should get

#### Explanation:

Consider the numerator first: even if you subtract

The denominator as well BUT not as fast as the numerator!

So the numerator will "win"and in the limit the function will tend to

We can also write collecting

as