How do you find #lim cos(1/t)# as #t->oo#?
2 Answers
Dec 7, 2017
It is one.
Explanation:
Logically speaking, as
Since
Dec 7, 2017
# lim_(t rarr oo) cos(1/t) = 1 #
Explanation:
We have:
# lim_(t rarr oo) cos(1/t) = cos(lim_(t rarr oo) 1/t)#
# " " = cos 0 #
# " " = 1 #
We can see that the graph of
graph{cos(1/x) [-6, 6, -2, 2]}