Question

How do you find `\lim _ { n \rightarrow + \infty } ( \frac { n - 1} { n + 2} ) ^ { 5}`?

Answer 1

`1`

Explanation:

`\lim _ { n \rightarrow + \infty } ( \frac { n - 1} { n + 2} ) ^ { 5} =`

`lim_(n->oo)((1-1/n)/(1+2/n))^5=1^5=1`