How do you find #lim (sqrt(x+1)+1)/(sqrt(x+1)-1)# as #x->0^+# using l'Hospital's Rule or otherwise?
This is not an indeterminate form. See below.
To determine which, consider an
We can write the form of the limit as
There is no limit.
For small positive
So there is no limit :(
We have a 2-sided limit.
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