How do you find #lim tantheta# as #theta->0#?

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Gió Share
Jan 9, 2017

Answer:

I found zero.

Explanation:

I would try this:
#lim_(theta->0)(tan(theta))=lim_(theta->0)(sin(theta)/cos(theta))=#
As #theta->0#:
#sin(theta)->0#
#cos(theta)->1#
So you should get #0/1=0#

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