Question

How do you find `lim tantheta` as `theta->(pi/2)^+`?

Answer 1

`tan theta = sintheta/costheta`

As `theta rarr (pi/2)^+`,

`sinthetararr1` and

`cos theta rarr 0^-`. (`cos theta` is negative in the second quadrant.)

Therefore, `theta rarr (pi/2)^+`,

`tan theta rarr -oo`