# How do you find #lim (x+1)^(3/2)-x^(3/2)# as #x->1^+#?

##### 1 Answer

Jan 4, 2017

#### Explanation:

The function is continuous through x = 1 so you can just plug in the value x = 1 to get

Jan 4, 2017

The function is continuous through x = 1 so you can just plug in the value x = 1 to get

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