Question

How do you find `lim (x^2-x+4)/(3x^2+2x-3)` as `x->oo`?

Answer 1

`1/3`

Explanation:

Divide numerator and the denominator by `x^2`. Accordingly, it is `(1-1/x +4/x^2)/(3+2/x -3/x^2)`. Now applying the limit `x-> oo`, it becomes

= `1/3`