How do you find #\lim _ { x \rightarrow - 2} ( x ^ { 3} + 6x )#?

1 Answer
Aug 1, 2017

#lim_(xrarr-2)[x^3+6x] = color(blue)(-20#

Explanation:

This limit can be found by substituting #-2# in for #x#:

#lim_(xrarr-2) [x^3 + 6x] = (-2)^3 + 6(-2)#

#= color(blue)(ul(-20#

A graph to check:

graph{x^3+6x [-18.6, 13.87, -23.36, -7.11]}