# How do you find other zeros given one zero f(x)=x^3-8x^2+4x+48; 4?

Jan 27, 2017

$- 2 \mathmr{and} 6$.

#### Explanation:

$\left(x - 4\right)$ is a factor of f.

Upon division by (x - 4), the other factor of f is obtained as

${x}^{2} - 4 x - 12 = \left(x - 6\right) \left(x + 2\right)$.

So, the other roots are given by

$x - 6 = x + 2 = 0$