# How do you find p(-4x) given p(x)=x^2-5x?

##### 1 Answer
Feb 7, 2017

See the entire solution process below:

#### Explanation:

To find $p \left(- 4 x\right)$ we must substitute $\textcolor{red}{- 4 x}$ for each occurrence of $\textcolor{red}{x}$ in the function $p \left(x\right)$.

$p \left(\textcolor{red}{x}\right) = {\textcolor{red}{x}}^{2} - 5 \textcolor{red}{x}$ becomes:

$p \left(\textcolor{red}{- 4 x}\right) = {\left(\textcolor{red}{- 4 x}\right)}^{2} - \left(5 \times \textcolor{red}{- 4 x}\right)$

$p \left(\textcolor{red}{- 4 x}\right) = 16 {x}^{2} - \left(- 20 x\right)$

$p \left(\textcolor{red}{- 4 x}\right) = 16 {x}^{2} + 20 x$