How do you find #p(-4x)# given #p(x)=x^2-5x#?

1 Answer
smendyka
Feb 7, 2017

See the entire solution process below:

Explanation:

To find #p(-4x)# we must substitute #color(red)(-4x)# for each occurrence of #color(red)(x)# in the function #p(x)#.

#p(color(red)(x)) = color(red)(x)^2 - 5color(red)(x)# becomes:

#p(color(red)(-4x)) = (color(red)(-4x))^2 - (5 xx color(red)(-4x))#

#p(color(red)(-4x)) = 16x^2 - (-20x)#

#p(color(red)(-4x)) = 16x^2 + 20x#

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