How do you find #p(-6)# given #p(a)=a^3-4a#?

1 Answer
Jan 31, 2017

See the entire solution process below:

Explanation:

To find #p(-6)# substitute #color(red)(-6)# for each occurrence of the variable #color(red)(a)# in the function from the problem:

#p(color(red)(a)) = color(red)(a)^3 - 4color(red)(a)# becomes:

#p(color(red)(-6)) = color(red)(-6)^3 - (4 xx color(red)(-6))#

#p(color(red)(-6)) = -216 - (-24)#

#p(color(red)(-6)) = -216 + 24#

#p(color(red)(-6)) = -192#