# How do you find p(-6) given p(a)=a^3-4a?

Jan 31, 2017

See the entire solution process below:

#### Explanation:

To find $p \left(- 6\right)$ substitute $\textcolor{red}{- 6}$ for each occurrence of the variable $\textcolor{red}{a}$ in the function from the problem:

$p \left(\textcolor{red}{a}\right) = {\textcolor{red}{a}}^{3} - 4 \textcolor{red}{a}$ becomes:

$p \left(\textcolor{red}{- 6}\right) = {\textcolor{red}{- 6}}^{3} - \left(4 \times \textcolor{red}{- 6}\right)$

$p \left(\textcolor{red}{- 6}\right) = - 216 - \left(- 24\right)$

$p \left(\textcolor{red}{- 6}\right) = - 216 + 24$

$p \left(\textcolor{red}{- 6}\right) = - 192$