Question

How do you find `p(x-4)` given `p(a)=a^3-5`?

Answer 1

`p(x - 4) = x^3 - 12x^2 + 48x - 69`

Explanation:

Replace `a` with `x - 4`:

`p(a) = a^3 - 5`

`p(x - 4) = (x - 4)^3 - 5`

`p(x - 4) = x^3 + 3x^2(-4) + 3x(-4)^2 - 4^3 - 5`

`p(x - 4) = x^3 - 12x^2 + 48x - 69`