# How do you find taylor polynomials of degree n approximating #5/(2-2x)# for x near 0?

##### 1 Answer

Jul 28, 2016

#### Explanation:

If

#1/(1-x) = sum_(n=0)^oo x^n#

Hence:

#5/(2-2x) = 5/(2(1-x)) = 5/2*1/(1-x) = 5/2 sum_(n=0)^oo x^n = sum_(n=0)^oo 5/2x^n#