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How do you find the 93rd term of the arithmetic sequence with first term 23 and 10th term 77?

1 Answer

Jul 1, 2017

$575$ $575$

Explanation:

The formula for an arithmetic sequence is $a + (n - 1) d = x$ $a+(n-1)d=x$

Here you already have the first term, $a = 23$ $a=23$ .

Now you just have $23 + (10 - 1) d = 77 \equiv 9 d = 54 \equiv d = \frac{54}{9} = 6$ $23+(10-1)d=77-=9d=54-=d=54/9=6$ .

Now you have $a$ $a$ and $d$ $d$ . For the 93rd term, we do $23 + (93 - 1) 6 = 23 + (92) 6 = 575$ $23+(93-1)6=23+(92)6=575$ .

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