How do you find the 93rd term of the arithmetic sequence with first term 23 and 10th term 77?

1 Answer
Jul 1, 2017

575575

Explanation:

The formula for an arithmetic sequence is a+(n-1)d=xa+(n1)d=x

Here you already have the first term, a=23a=23.

Now you just have 23+(10-1)d=77-=9d=54-=d=54/9=623+(101)d=779d=54d=549=6.

Now you have aa and dd. For the 93rd term, we do 23+(93-1)6=23+(92)6=57523+(931)6=23+(92)6=575.