How do you find the absolute value of $-7-2i$ ?

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Answer 1 · 2017-04-02T09:20:15

$abs(-7-2i) = sqrt(53)$

The absolute value of a complex number is essentially its (Euclidean) distance from $0$ , which we can find with the help of Pythagoras.

$abs(x+iy) = sqrt(x^2+y^2)$

So in our example:

$abs(-7-2i) = sqrt((-7)^2+(-2)^2) = sqrt(49+4) = sqrt(53)$

How do you find the absolute value of -7-2i-7-2i?